Web12 jun. 2024 · If you don't want to allow duplicates and if you don't necessarily need to implement the java.util.List interface, you may want to consider using … WebA set is simply a collection that can contain no duplicates so it sounds perfect for you. It is also very simple to implement. For example: Set mySet = new HashSet (); This would provide you a set that can hold Objects of type String. To add to the set is just as simple: mySet.add ("My first entry!");

Java Array, Finding Duplicates - Stack Overflow

Web6 mei 2012 · A PriorityQueue in Java does not have any restriction with regard to duplicate elements. If you want to ensure that two identical items are never present in the priority queue at the same time the simplest way would be to maintain a separate Set in parallel with the priority queue. t-shirt printing wrexham

How to configure Java Priority Queue to ignore duplicates?

Try this code for removing duplicates using Hashset. public static Integer [] removeDuplicateUsingSet (Integer [] example) { List inputList = Arrays.asList (example); Set inputSet = new HashSet (inputList); Integer [] ints = new Integer [inputSet.size ()]; int index = 0; for (Integer i : inputSet) { ints ... Web16 dec. 2013 · For each addition to the ArrayList you will have to iterate over all previous entries and check if duplicates entry exists (You can use .contains ()) which is O (N). Better I would suggest use a set. Firstly, use equals to compare strings. And lastly, you can use contains method to check if the item already exists. Web4 apr. 2016 · List list = new ArrayList<> (); addToList (list, "one"); addToList (list, "two"); addToList (list, "three"); addToList (list, "two"); Only disadvantage here is we need to call our custom addToList () method everytime instead of list.add () Share Follow answered Nov 20, 2016 at 6:33 Naresh Joshi 4,122 34 43 Nice and simple. philosophy\\u0027s 18